The question is:
" How many grams are in 2.3 x 10^-4 moles of calcium phosphate.
I worked out that in scientific notation, it's basically saying:
How many grams are in 0.0023 moles of Ca₃(PO₃)₂
So far, this is my working out:
Ca ^ 3 (Calcium = 40 x 3 = 120)
120 grams so far
Then, it gets to the difficult part. So, PO^3 is basically saying P (Phosphorus = 31) So 31 so far ( Don't add up )
And O ( Oxygen = 16 x 3 = 48)
Then you can do 31 + 48 = 79, which means you have to multiply 79 by two I believe, meaning it will be 158
So, 158 + 120 = 278
So, 0.00023 / 278 = 8.2grams
However, this could be incorrect as it may be 79 squared, so 79 x 79 = 6241 + 120 = 6361, and if we look at 2.3 x 10 ^ -4,
In scientific notation, it basically means 0.0023 I believe...
So 6361 and 0.0023 (-4)
How many grams = 0.00023 / 6351 = 3.6grams
That can't really be right if it's per mole though, so I honestly have no idea what to suggest for it, if you're around B/A In Science, please help, I've already researched it and I haven't found any useful websites or calculator websites
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